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Electrif field between plates. Please explain. Cheers heaps!?
In a cathode-ray tube (CRT), an electron travels in a vacuum and enters a region between two "deflection" plates which have equal and opposite charges. The dimensions of each plate are 12 cm by 4 cm, and the gap between them is 2.5 mm.
During a 0.001 s interval while it is between the plates, the change of the momentum of the electron is < 0,5.60e-17,0 > kg m/s.
1)What is the electric field between the plates?
Hint: remember the Momentum Principle (the relationship between Impulse and change in momentum.)
2) What is the charge (both magnitude and sign) of the upper plate?
How on earth do you do this? Cheers heapss!
Momentum change ∆p = ∫F*dt. The field between the plates is uniform, so the force is constant. Then
∆p = F*t
you are given ∆p and t, solve for F:
F = ∆p/t
The force on an electron in a uniform field F = qe*E, so you can find the field magntitude:
E = ∆p/(t*qe)
The field between the plates is σ/ε0, where σ it the surface charge density. σ = Q/A, where Q is the total charge on the plate and A the area.
σ/ε0 = ∆p/(t*qe)
Q = A*ε0*∆p/(t*qe)
A = 012*.04 m²
ε0 = 8.89*10^-12 F/m
∆p = 0.56*10^-17 kg-m/s
t = 0.001 s
qe = -1.6*10^-19 C
If positive momentum change is upward, then the upper plate is positively charged.
The separation doesn't matter unless you need the voltage difference between the plates also.
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